2cos^2(3x)=1+2sin^2(3x)

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Solution for 2cos^2(3x)=1+2sin^2(3x) equation:


Simplifying
2cos2(3x) = 1 + 2sin2(3x)

Remove parenthesis around (3x)
2cos2 * 3x = 1 + 2sin2(3x)

Reorder the terms for easier multiplication:
2 * 3cos2 * x = 1 + 2sin2(3x)

Multiply 2 * 3
6cos2 * x = 1 + 2sin2(3x)

Multiply cos2 * x
6cos2x = 1 + 2sin2(3x)

Remove parenthesis around (3x)
6cos2x = 1 + 2in2s * 3x

Reorder the terms for easier multiplication:
6cos2x = 1 + 2 * 3in2s * x

Multiply 2 * 3
6cos2x = 1 + 6in2s * x

Multiply in2s * x
6cos2x = 1 + 6in2sx

Solving
6cos2x = 1 + 6in2sx

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Divide each side by '6os2x'.
c = 0.1666666667o-1s-2x-1 + in2o-1s-1

Simplifying
c = 0.1666666667o-1s-2x-1 + in2o-1s-1

Reorder the terms:
c = in2o-1s-1 + 0.1666666667o-1s-2x-1

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